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Full Stack Developer Without Degree: How to Become One

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If you're interested in becoming a Full Stack Developer without a degree, we've put together some tips and resources to help you get started. Learn the Fundamentals The first step to becoming a Full Stack Developer is to learn the fundamentals of coding. You can start with HTML, CSS, and JavaScript, which are the building blocks of web development. There are plenty of free resources available online, such as Codecademy and FreeCodeCamp, which offer interactive courses that teach you the basics of web development. Once you have a solid understanding of the basics, you can move on to more advanced topics such as back-end development, databases, and frameworks. You can learn these topics through online courses or by working on personal projects. Build a Portfolio One of the most important things you can do as a Full Stack Developer is to build a portfolio. Your portfolio should showcase your skills and experience and demonstrate your ability to build real-world applications. You c...
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Nth node from end of linked list (DSA)

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Problem Statement:(👈click here for GFG)

Given a linked list consisting of L nodes and given a number N. The task is to find the Nth node from the end of the linked list.

Example 1:

Input:
N = 2
LinkedList: 1->2->3->4->5->6->7->8->9
Output: 8
Explanation: In the first example, there
are 9 nodes in linked list and we need
to find 2nd node from end. 2nd node
from end is 8.  

Example 2:

Input:
N = 5
LinkedList: 10->5->100->5
Output: -1
Explanation: In the second example, there
are 4 nodes in the linked list and we
need to find 5th from the end. Since 'n'
is more than the number of nodes in the
linked list, the output is -1.
Your Task:
The task is to complete the function getNthFromLast() which takes two arguments: reference to head and N and you need to return Nth from the end or -1 in case node doesn't exist.

Note:
Try to solve in a single traversal.

Expected Time Complexity: O(N).
Expected Auxiliary Space: O(1).

Constraints:
1 <= L <= 106
1 <= N <= 106

Solution:

class Solution {
    //Function to find the data of nth node from the end of a linked list
    getNthFromLast(head, n)
    {
        let len = 0;
        let curr = head;
        
        //counting the length of the linked list
        while(curr != null) {
            len++;
            curr = curr.next;
        }
        
        //if n is greater than length of linked list, return -1
        if(n > len) {
            return -1;
        }
        
        //finding the position of node to be returned from beginning
        let position = len - n + 1;
        curr = head;
        let count = 1;
        
        //iterating till the position to get the node
        while(count < position) {
            curr = curr.next;
            count++;
        }
        
        //returning the data of the node
        return curr.data;
    }
}
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