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If you're interested in becoming a Full Stack Developer without a degree, we've put together some tips and resources to help you get started. Learn the Fundamentals The first step to becoming a Full Stack Developer is to learn the fundamentals of coding. You can start with HTML, CSS, and JavaScript, which are the building blocks of web development. There are plenty of free resources available online, such as Codecademy and FreeCodeCamp, which offer interactive courses that teach you the basics of web development. Once you have a solid understanding of the basics, you can move on to more advanced topics such as back-end development, databases, and frameworks. You can learn these topics through online courses or by working on personal projects. Build a Portfolio One of the most important things you can do as a Full Stack Developer is to build a portfolio. Your portfolio should showcase your skills and experience and demonstrate your ability to build real-world applications. You c...

Detect cycle in an undirected graph (DSA)

 


Problem Statement:(👈click here for GFG)

Given an undirected graph with V vertices and E edges, check whether it contains any cycle or not. Graph is in the form of adjacency list where adj[i] contains all the nodes ith node is having edge with.

Example 1:

Input:  
V = 5, E = 5
adj = {{1}, {0, 2, 4}, {1, 3}, {2, 4}, {1, 3}} 
Output: 1
Explanation: 

1->2->3->4->1 is a cycle.

Example 2:

Input: 
V = 4, E = 2
adj = {{}, {2}, {1, 3}, {2}}
Output: 0
Explanation: 

No cycle in the graph.
Your Task:
You don't need to read or print anything. Your task is to complete the function isCycle() which takes V denoting the number of vertices and adjacency list as input parameters and returns a boolean value denoting if the undirected graph contains any cycle or not, return 1 if a cycle is present else return 0.

NOTE: The adjacency list denotes the edges of the graph where edges[i] stores all other vertices to which ith vertex is connected.
 
Expected Time Complexity: O(V + E)
Expected Space Complexity: O(V)

Constraints:
1 ≤ V, E ≤ 105
Solution:
class Solution {
  // Function to detect cycle in an undirected graph.
  isCycle(V, adj) {
    // Create an array to keep track of visited vertices
    let visited = new Array(V).fill(false);

    // Perform DFS from each unvisited vertex
    for (let i = 0; i < V; i++) {
      if (!visited[i]) {
        if (dfs(i, -1, visited, adj)) {
          // If a cycle is detected, return true
          return 1;
        }
      }
    }

    // If no cycle is detected, return false
    return 0;
  }
}

// Helper function to perform DFS
function dfs(vertex, parent, visited, adj) {
  // Mark the current vertex as visited
  visited[vertex] = true;

  // Traverse all the adjacent vertices
  for (let i = 0; i < adj[vertex].length; i++) {
    let adjVertex = adj[vertex][i];

    // If the adjacent vertex is not visited, visit it and continue DFS
    if (!visited[adjVertex]) {
      if (dfs(adjVertex, vertex, visited, adj)) {
        return true;
      }
    }
    // If the adjacent vertex is visited and not the parent of the current vertex, a cycle is detected
    else if (adjVertex != parent) {
      return true;
    }
  }

  // If no cycle is detected, return false
  return false;
}

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